Question

In a wind tunnel experiment, a team uses pitot tube to measure flow velocity, given the pressure difference equals 50 Pa, calculate the velocity. Assume p 1.16 kg/m a. 100.18 m/s b. 20.2 m/s c. 19.8 m/s d. 9.3 m/s

Answer 1

d. 9.3 m/s

Step-by-step explanation:

Pressure difference = ΔP = P₁ - P₂ = 50 Pa

Density of air = ρ = 1.16 kg/m³

For a Pitot tube

`P_1-P_2=(1)/(2)\rho v^2\\\Rightarrow \Delta P=(1)/(2)\rho v^2\\\Rightarrow v=\sqrt{(2* \Delta P)/(\rho)}\\\Rightarrow v=\sqrt{(2* 50)/(1.16)}=9.28\approx 9.3\ m/s`

∴ Flow velocity is 9.3 m/s