Question

(27x^4-18x^3+9x^2) divided by 3x

Answer 1

9x^3-6x^2+3x

Basically with this you just wanna simplify each term one-by-one.

For instance, look at the first term, 27x^4

Imagine 27x^4/3x

3 goes into 27 9 times, and x goes into x^4 4 times (cuz x to the power of 4 is just x times x times x times x)

So you’re left with 9x^3

Answer 2

`9x^3-6x^2+3x`

Explanation:

We have the following:

`(27x^4-18x^3+9x^2)/(3x)`

which can be separeted like this:

`(27x^4)/(3x) -(18x^3)/(3x) +(9x^2)/(3x)`

and using the rule:

`(x^m)/(x^n)=x^(m-n)`

in other words we substract the exponents at the moment we make the division, and also dividing the coefficients (
`(27)/(3) =9,(18)/(3) =6, (9)/(3) =3`) we get the following:

`9x^(4-1)-6x^(3-1)+3x^(2-1)\\=9x^3-6x^2+3x`

the answer is:
`9x^3-6x^2+3x`