Question

Correct answers only please!

Use the following information to find your course average in AMDM, if Homework is weighted 20%, Class Participation is 25%, Test Grades are 30%, and Final Exam is 25%.


 Homework {90, 94, 96, 90}
 Class Participation {95, 99}
 Test Grades {87, 75, 82 ,85}
Final Exam Grade {71}

18.5 + 24.25 + 24.675 + 17.75




A. 85

B. 88.5

C. 87

D. 89

Answer 1

71%

Explanation:

Answer 2

First question : A. 85,

Second question : 71%

Explanation:

First question :

Percentage marks in home work,

90, 94, 96, 90,

So, the average percentage marks in home work =
`(90+94+96+90)/(4)` = 92.5

∵ Weightage in home work = 20%,

So, the weightage marks in home work = 20% of 92.5 = 0.20(92.5) = 18.5

Similarly, the class participation is weighted 25%,

So, the weightage marks in class participation

`=25\%\text{ of }(95+99)/(2)`

= 24.25

The test grade weighting 30%,

So, the weightage marks in class participation

`=30\%\text{ of }(87+75+82+85)/(4)`

= 24.675

The final exam weightage is 25%,

So, the weightage marks in final exam,

`25\%\text{ of }71`

= 17.75

Hence, the total average = 18.5 + 24.25 + 24.675 + 17.75 ≈ 85

Second question :

Given,

Averages of Mark in his AMDM maths class,

Homework : 95,

Quiz average : 80,

Test average : 67,

Final average : 60,

Also, the weightage,

In home work is 10%,

In Quiz test is 20%

In test is 50%

In final exam is 20%

Hence, Marks class average =
`(10)/(100)* 95+(20)/(100)* 80 + (50)/(100)* 67+(20)/(100)* 60`

= 71 %