Question

6(8-x)(x+4)=0 what’s the solution set?

Answer 1

`x_(1) = -4\\\\x_(2) = 8`

Explanation:

6(8-x)(x+4)=0

(48 -6x )(x+4) = 0

48x +192 -6x^2 -24x = 0

6x^2 -24x -192=0

using quadratic formula:

`x =\frac{-b+-\sqrt{b^(2)-4*a*c}}{2*a}`

a= 6 b= -24 c= -192

we have:

`x_(1) = -4\\\\x_(2) = 8`