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18 votes
Solve 2w2–64 = 0, where w is a real number.

1 Answer

6 votes

Answer:

w = 4√2

Explanation:

2w^2 - 64 = 0

=> 2w^2 = 64

=> w^2 = 32

=> w = √ 32

=> w = √ [(2 x 2) x (2 x 2) x 2]

=> w = 2 x 2 x √ 2

=> w = 4√2

User Jeanell
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