Answer:
Part 1) m∠EFG=94°
Part 2) m∠GFH=86°
Explanation:
we know that
m∠EFG+m∠GFH=180° -----> by linear pair (given problem)
we have
m∠EFG=3n+22
m∠GFH=2n+38
substitute the values
(3n+22)°+(2n+38)°=180°
Solve for n
(5n+60)=180
5n=180-60
5n=120
n=24
Find the measure of angle EFG
m∠EFG=3n+22
substitute the value of n
m∠EFG=3(24)+22=94°
Find the measure of angle GFH
m∠GFH=2n+38
substitute the value of n
m∠GFH=2(24)+38=86°