Answer:
![125i](https://img.qammunity.org/2020/formulas/mathematics/middle-school/i4p1m253w2h7dhfweyzg40sajt3jye0q0c.png)
Explanation:
When we have potential expression that include imaginary numbers, we have to consider some basic results, because these imaginary potential expression are cyclical.
We know that:
![i=√(-1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/zonqc68oti56jvhhkisglqsc9z9pqyvjgo.png)
So, elevating both members to a third power, we have:
![i^(3)=(√(-1) )^(3)=\sqrt{(-1)^(3) }=√(-1)=i](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6svmbqjpz8m5eicolwkncticao5hu0j4tq.png)
So,
, which is the beginning, that's why we say that it's like a cycle.
So, from the problem, we have:
![5^(3) i^(9)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ihm1lr5rtnpssqaytgf8ups673u5e502q8.png)
To solve this, we consider the operations from the beginning:
; and
; because
![i^(3)=i](https://img.qammunity.org/2020/formulas/mathematics/middle-school/zlnzqx4d6369fs49uhwfucqfl2c0ewpegg.png)
Therefore, the result would be
![125i](https://img.qammunity.org/2020/formulas/mathematics/middle-school/i4p1m253w2h7dhfweyzg40sajt3jye0q0c.png)