Question

4) The sum of three consecutive even numbers

is 48. What are the smallest of these
numbers?

Answer 1

14

16

Explanation:

a + b + c =48

an even number is written as 2n, where n is any integer number

a= 2n = first even number

b= 2n +2 = second consecutive even number

c = 2n +4 = third consecutive even number

so we have:

2n + 2n+ 2 + 2n + 4 = 48

6n + 6 =48

6n = 48-6

6n = 42

n = 42/6

n=7

a= 2n = 2*7 = 14

b= 2n +2 = 2*7 + 2 = 16

c = 2n + 4 = 2*7 + 4 = 18

the answer is: 14 and 16