Question

Body temperatures of healthy humans are distributed nearly normally with mean 98.2oF and standard deviation 0.73oF. What is the cutoff for the highest 10% of human body temperatures?

Answer 1

`99.1`oF is the cutoff for the highest 10% of human body temperatures

Step-by-step explanation:

The confidence interval for this problem is
`90` %

We will first evaluate the z-value for 90% confidence interval considering it one tailed.

Z from the statics table is equal to
`1.28\\`

Formula for z - value

`z= (x-u)/(\alpha )`

where

x represents the required cut off value

u represents the mean value

and α represents the standard deviation

Substituting the values in above equation, we get -

`1.28  = (x-98.2)/(0.73) \\0.9344= x-98.2\\x= 0.9344+98.2\\x=99.1\\`

Hence,

`99.1`oF is the cutoff for the highest 10% of human body temperatures