Question

A tray contains 12 ham sandwiches, 10 turkey sandwiches, and 8 peanut butter sandwiches. If Carrie takes a sandwich from the tray at random, what is the probability that she takes a ham sandwich?

Answer 1

`(2)/(5)`or 0.4

Explanation:

Number of ham sandwiches=12

Number of turkey sandwiches=10

Number of peanut butter= 8

Total number of outcomes= 12+10+8

Total number of outcomes=30

Let E be the event of getting a ham sandwich

Favorable case to E= 12

Probability =
`(favourable case )/( total number of outcomes)`

P(E)=
`(12)/(30)`

P(E)=
`(2)/(5)`

P(E)=0.4

Hence , the correct answer is
`(2)/(5)` or 0.4