133k views
5 votes
Required information NOTE: This is a mult-part Once an answer is submitted, you will be unable to return to this part Consider a positive integer n Put the steps in cortect order to prove that if n is even, then 7n+ 4 is even (You must provide an answer before moving to the next part) es Rank the options below This is 2 times an integer, so it is even Since n is even, it can be written as 2k for some integer k Then 7n+ 414k+ 4-2(7k+ 2)

1 Answer

2 votes

Answer with Step-by-step explanation:

Suppose a positive integer n.

We have to prove that if n is even , then 7n+4 is even .

We are given some steps in order to prove this we have to arrange in correct order.

If n is even, it can be written as 2k

n=2k for some integer k

Then substitute the value of n then we get


7(2k)+4


14k+4


2(7k+2)

This is 2 times an integer , so it is even.

Hence, proved.

User Longfish
by
5.1k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.