Answer with Step-by-step explanation:
Suppose a positive integer n.
We have to prove that if n is even , then 7n+4 is even .
We are given some steps in order to prove this we have to arrange in correct order.
If n is even, it can be written as 2k
n=2k for some integer k
Then substitute the value of n then we get
![7(2k)+4](https://img.qammunity.org/2020/formulas/mathematics/college/1zeyz0zu58j9nnle7u2mz4pzhiu2454po1.png)
![14k+4](https://img.qammunity.org/2020/formulas/mathematics/college/hf1n7j4bk3775psn0iexei433nlnz8q3f4.png)
![2(7k+2)](https://img.qammunity.org/2020/formulas/mathematics/college/qbwdeyezootm7xm2bkkh643vk2qssazqk9.png)
This is 2 times an integer , so it is even.
Hence, proved.