Question

If you want to construct an LC circuit that resonates at 0.9 MHz, what should the inductor be if the capacitor is 3.1 pF ?

Answer 1

`L=0.0101* 10^(-6)H`

Step-by-step explanation:

We have given resonates frequency f=0.9 MHz
`=0.9* 10^9Hz`

The capacitance of the capacitor C =3.1 pF
`=3.1* 10^(-12)F`

For an LC circuit resonance frequency is given by
`f=(1)/(2\pi √(LC))`

`0.9* 10^9=\frac{1}{2* 3.14\sqrt{3.1* 10^(-12)L}}`

`0.81* 10^(18)=(1)/(4* 9.8596* 3.1* 10^(-12)L)`

`L=0.0101* 10^(-6)H`