Question

An L−R−C series circuit has 91.5 Ω , and the amplitude of the voltage across the resistor is 36.0 V . What is the average power delivered by the source? Express your answer with the appropriate units.

Answer 1

14.16 W

Step-by-step explanation:

We have given impedance Z=91.5 ohm

Voltage across the resistor = 36 V

We have to find the power delivered by the source

We know that according to telegens theorem , the absorbed = power delivered

So the voltage across the resistor = 36 V

Current in the RLC circuit
`i=(V)/(Z)=(36)/(91.5)=0.3934A` this current will be same in the whole circuit as it is a series RLC circuit

Now the power absorbed by the resistor
`P=i^2R=0.3934^2* 91.5=14.16W`

As the power absorbed = power delivered

So power delivered by the source =14.16 W