Question

A glass plate whose index of refraction is 1.66 is immersed in a liquid. The surface of the glass is inclined at an angle of 44º with the vertical. A horizontal ray in the glass is incident on the interface. When the liquid is a certain alcohol, the incident ray arrives at the interface at the critical angle. The index of refraction of the alcohol is closest to: O A. 1.13 OB. 1.17 O C. 1.15 O D. 1.11

Answer 1

C. 1.15

Step-by-step explanation:

The formula for the critical angle is:

`{sin\theta_(critical)}=\frac {n_r}{n_i}`

Where,

`{\theta_(critical)}` is the critical angle

`n_r` is the refractive index of the refractive medium. ( Alcohol , ? )

`n_i` is the refractive index of the incident medium. ( Glass, 1.66 )

Critical angle = 44º

Applying in the formula as:

`{sin\theta_(critical)}=\frac {1}{1.523}`

`{sin\ 44^0}=\frac {n_r}{1.66}`

`{n_r}=1.15`