Question

A beam of light is traveling in air and strikes a material. The angles of incidence and refraction are 63.0° and 47.0° respectively. Obtain the speed of light in the material.

Answer 1

Speedd of the light in the medium is
`2.459* 10^(8)m/s`

Step-by-step explanation:

According to Snell's law we have

`\mu _(1)sin(\theta _(i))=\mu _(2)sin(\theta _(r))`

Since incidence medium is air thus we have

`\mu _(1)=1`

Applying values we get

`1* sin(63^(o))=\mu _(2)sin(47^(o))\\\\\therefore \mu _(2)=(sin(63))/(sin(47))=1.22`

Now we know that speed of light in any medium is given by

`v=(c)/(\mu )`

where
`\mu` is the refractive index of the medium and 'c' is the speed of light in vacuum

Thus upon applying values we get

`v=(3* 10^(8))/(1.22 )\\\\\therefore v=2.459* 10^(8)m/s`