Question

What is the output of the following program when the method is called with 4?

void unknown(int n)

{

if(n>0)

unkown(n-1);

System.out.print("?");

}

A. None of the other answers

B.???

C.?????

D.????

Answer 1

C. ?????

Step-by-step explanation:

Given code:

void unknown(int n)

{

if(n>0)

unkown(n-1);

System.out.print("?");

}

Calling code: unknown(4)

This is a recursive invocation of unknown function and causes ? to be printed 5 times once each for following values of n.

• unknown invocation with n=4

• unknown invocation with n=3

• unknown invocation with n=2

• unknown invocation with n=1

• unknown invocation with n=0

When n becomes 0, termination condition is reached and the function returns.

So the output is ?????