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a ball is thrown vertically upward from the ground with an initial velocity of 60 ft/sec. how high will the ball go?

User Yunus Kula
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1 Answer

4 votes

Answer:

The ball will go to maximum height of 56.25 meters.

Explanation:

It is given that, a ball is thrown vertically upward from the ground. Initial velocity of the ball, v = 60 ft/sec

Initial height is 0 as the ball is thrown from ground. The equation of projectile is given by :


h(t)=-16t^2+vt+h

h = 0


h(t)=-16t^2+60t..............(1)

We need to find the maximum height reached by the ball. For maximum height,


(dh(t))/(dt)=0


(d(-16t^2+60t))/(dt)=0

t = 1.875 seconds

Put the values of t in equation (1). So,


h(t)=-16(1.875)^2+60(1.875)

h(t) = 56.25 meters

So, the ball will go to maximum height of 56.25 meters. Hence, this is teh required solution.

User Hridya Pv
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