Answer:
False
Explanation:
Given that 3 objects are drawn from 4 distinct objects with replacement.
Whenever we draw with replacement combination formula will not be appropriate.
The real solution would be as follows:
I object can be taken in 4 ways
II object also in 4 ways (since replacement)
and III object also in 4 ways
Hence total number of ways to select 3 out of 4 distinct objects with repetition allowed
=
![4^3 =64](https://img.qammunity.org/2020/formulas/mathematics/college/lw1tcdjstfe99aa8cn9obxdyep82slceif.png)