Question

A resistor with resistance R = 2 ohms is connected to an ac power supply. If the maximum voltage produced by the power supply is 17 V, then what is the average power dissipated by the resistor? Select one: O a. 72 W O b. 290 W O c. 17 W O d. 140 W

Answer 1

The average power dissipated by the resistor is 72 Watt.

(a) is correct option.

Step-by-step explanation:

Given that,

Resistance = 2 ohm

Voltage = 17 V

We need to calculate the
`V_(rms)`

Using formula of
`V_(rms)`

`V_(rms)=(V)/(√(2))`

Put the value into the formula

`V_(rms)=(17)/(√(2))`

`V_(rms)=12.02\ V`

We need to calculate the average power dissipated by the resistor

Using formula of power dissipated

`P_(d)=V_(rms)* I_(rms)`

`P_(d)=V_(rms)* (V_(rms))/(R)`

Put the value into the formula

`P_(d)=12.02*(12.02)/(2)`

`P_(d)=72.24 = 72\ Watt`

Hence, The average power dissipated by the resistor is 72 Watt.