Question

A 2 kg mass on a spring with spring constant k = 1 is not oscillating. The system is critically damped. What is the coefficient of friction?

Answer 1

`b=\pm 2√(2)`

Step-by-step explanation:

The differential equation which describes the spring mass system is

my''+by'+ky=0

This system will be critically damped if
`b^2-4mk=0` here b is the coefficient of friction m is the mass and k is the spring constant

We have given k=1 and m=2

So
`b^2-4* 2* 1=0`

`b^2=8`

`b=\pm 2√(2)`