Question

What is the velocity of flow in an asphalt channel that has a hydraulic radius of 3.404 m, length of 200 m and bed slope of 0.005?

Answer 1

The velocity of flow is 10.0 m/s.

Step-by-step explanation:

We shall use Manning's equation to calculate the velocity of flow

Velocity of flow by manning's equation is given by

`V=(1)/(n)R^(2/3)S^(1/2)`

where

n = manning's roughness coefficient

R = hydraulic radius

S = bed slope of the channel

We know that for an asphalt channel value of manning's roughness coefficient = 0.016

Applying values in the above equation we obtain velocity of flow as

`V=(1)/(0.016)* 3.404^(2/3)* 0.005^(1/2)\\\\\therefore V=10.000m/s`