Answer:
No. of 100 W bulbs, n = 28,539 bulbs
Given:
Power of a single bulb = 100 W
Time period, T = 1 yr =
= 31,536,000 s
mass of matter, m = 1 g =
![1* 10^(-3)]](https://img.qammunity.org/2020/formulas/physics/college/dfc8c9a8bidm2brh6f7eofu7lctcmhgy4s.png)
Solution:
According to Eintein's mass-energy equivalence:
E =
![mc^(2)](https://img.qammunity.org/2020/formulas/physics/high-school/88kref9tvm1emuweqpsd2s5nc7d0oh66gm.png)
E =
![1* 10^(-3)* (3* 10^(8))^(2)](https://img.qammunity.org/2020/formulas/physics/college/xc53ms5gnqpg4yx0e7ekq3o46emxphn6jf.png)
E =
![9* 10^(13) J](https://img.qammunity.org/2020/formulas/physics/college/wlyy0wqnpy74r6u6ymwaa9gvf97hz6layg.png)
Power of a single bulb, P =
![(E)/(T)](https://img.qammunity.org/2020/formulas/physics/college/8aqtyjf3tmzciajyf65k0xkea3r8jjp5dg.png)
P =
![(9* 10^(13) )/(31,536,000)](https://img.qammunity.org/2020/formulas/physics/college/wneccqofrbho5y6kje4mv4jzzfp59hr3o6.png)
P = 28,53,881 W
No. of 100 W bulbs, n =
![(P)/(power of one bulb)](https://img.qammunity.org/2020/formulas/physics/college/im7ylsaargfkmbecukf5hghn7ycygnda3k.png)
n =
![(28,53,881)/(100)](https://img.qammunity.org/2020/formulas/physics/college/wpdcn84xw7v319n2h7r47hx7kh2jra63m2.png)
n = 28,539