Question

What charge is held by a 2.2 microfarad capacitor at a voltage of 6 V?

Answer 1

13.2\mu C

Step-by-step explanation:

The capacitance of the capacitor C = 2.2 microfarad
`=2.2* 10^(-6)F`

Voltage at the capacitor =6 V

The charge on the capacitor is equal to the product of capacitance and the voltage , so charge = capacitance ×voltage

So charge
`Q=CV=2.2* 10^(-6)* 6=13.2* 10^(-6)C=13.2\mu C`

Answer 2

Charge,
`q=1.32* 10^(-5)\ C`

Step-by-step explanation:

It is given that,

Capacitance,
`C=2.2\ \mu F=2.2* 10^(-6)\ F`

Voltage, V = 6 volts

We need to find the charge held by the capacitor. It is given by :

`q=C* V`

`q=2.2* 10^(-6)\ F * 6\ V`

q = 0.0000132 C

or

`q=1.32* 10^(-5)\ C`

So, the charge held by the capacitor is
`1.32* 10^(-5)\ C`. Hence, this is the required solution.