Answer:
The tension on each rope is 28.28 lb
Step-by-step explanation:
Given that,
Weight = 40 lb
Angle = 45°
We need to calculate the tension on each rope
Considering the symmetry of the system, the tension of each rope must be same
So,
![T\sin\theta+T\sin\theta=mg](https://img.qammunity.org/2020/formulas/physics/college/78cazoqqgqtrmdrve071y0sg2ydqzeo7ei.png)
Put the value into the formula
![2T\sin\theta=mg](https://img.qammunity.org/2020/formulas/physics/college/6a00cogmj84in3glajyq0adv2n9d61ynfi.png)
![T*\sin45=(40)/(2)](https://img.qammunity.org/2020/formulas/physics/college/6n0tnptqckfch22w7yrrhvqq4l8r6eslmf.png)
![T=(40√(2))/(2)](https://img.qammunity.org/2020/formulas/physics/college/f0lv8s6s0lmkb7ooybgv2ka8aegiwgd1nb.png)
![T=28.28\ lb](https://img.qammunity.org/2020/formulas/physics/college/gmxlpoia796sjf0h5e0n3mbgjrmj7jic7x.png)
Hence, The tension on each rope is 28.28 lb.