Question

The wavelength of the visible line in the hydrogen spectrum that corresponds to m = 5 in the Balmer equation is: A. 656 nm. B. 486 nm. C. 434 nm. D. 410 nm. E. None of these is correct.

Answer 1

The wavelength of the visible line in the hydrogen spectrum is 434 nm.

Step-by-step explanation:

It is given that, the wavelength of the visible line in the hydrogen spectrum that corresponds to n₂ = 5 in the Balmer equation.

For Balmer series, the wave number is given by :

`(1)/(\lambda)=R((1)/(n_1^2)-(1)/(n_2^2))`

R is the Rydberg's constant

For Balmer series, n₁ = 2. So,

`(1)/(\lambda)=1.097* 10^7* ((1)/(2^2)-(1)/(5^2))`

`\lambda=4.34* 10^(-7)\ m`

or

`\lambda=434\ nm`

So, the wavelength of the visible line in the hydrogen spectrum is 434 nm. Hence, this is the required solution.