Question

Two parallel wires carry currents in the same direction. If the currents in the wires are 1A and 4A and the wires are 5 m apart. Calculate the force between the 2 wires. Is it attractive or repulsive? Calculate the magnetic field midway between the wires.

Answer 1

`1.6* 10^(-7)` N

`2.4* 10^(-7)` N

Step-by-step explanation:

`i_(1)` = 1 A

`i_(2)` = 4 A

`r` = distance between the two wire = 5 m

`F` = Force per unit length acting between the two wires

Force per unit length acting between the two wires is given as

`F = (\mu _(o))/(4\pi )(2i_(1)i_(2))/(r)`

`F = (10^(-7))(2(1)(4))/(5)`

`F = 1.6* 10^(-7)` N

`r'}` = distance of each wire from the midpoint = 2.5 m

Magnetic field midway between the two wires is given as

`B = (\mu _(o))/(4\pi ) \left \left ( (2i_(2))/(r') \right - (2i_(1))/(r') \right \right ))`

`B = (10^(-7)) \left \left ( (2(4))/(2.5) \right - (2(1))/(2.5) \right \right ))`

`B = 2.4* 10^(-7)`