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By how much does the volume of an aluminum cube 4.00 cm on an edge increase when the cube is heated from 19.0°C to 67.0°C? The linear expansion coefficient of aluminum is 23.0 x 10^-6 /C°.

User Bvpx
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1 Answer

5 votes

Answer:

The volume of an aluminum cube is 0.212 cm³.

Step-by-step explanation:

Given that,

Edge of cube = 4.00 cm

Initial temperature = 19.0°C

Final temperature = 67.0°C

linear expansion coefficient
\alpha=23.0*10^(-6)/C^(\circ)

We need to calculate the volume expansion coefficient

Using formula of volume expansion coefficient


\beta=3\alpha

Put the value into the formula


\beta=3*23.0*10^(-6)


\beta=0.000069=69*10^(-6)/C^(\circ)

We need to calculate the volume


V= a^3


V=4^3


V=64\ cm^3

The change temperature of the cube is


\Delta T=T_(f)-T_(i)

Put the value into the formula


\Delta T=67-19 = 48^(\circ)C

We need to calculate the increases volume

Using formula of increases volume


\Delta V=V\beta\Delta T

Put the value into the formula


\Delta V=64*69*10^(-6)*48


\Delta V=0.212\ cm^3

Hence, The volume of an aluminum cube is 0.212 cm³.

User Joel Brewer
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