Question

Two particles with charges +2q and +q are separated by a distance r. The +2q particle has an electric field E at distance r and exerts a force F on the +q particle. What is the electric field of the +q particle at the same distance and what force does it exert on the +2q particle?

A. E/2, F/2.
B. E, F/2.
C. E/2, F.
D. E,F.

Answer 1

C. E/2, F.

Step-by-step explanation:

Suppose two particles as A and B which are separated by a distance of r.

And the charge on the particle A is +2q and the charge on the particle B is +q.

According to the question, the electric field at a distance of r on the charge +2q is E.

`E=\frac{2q}{4\pi\epsilon{0}r^2 }`.

And the force on the +q charge at a distance of r is F.

`F=\frac{(q)(2q)}{4\pi\epsilon{0}r^2 }`.

Now, the electric field can be calculated at +q charge on the same distance will be,

`E'=\frac{q}{4\pi\epsilon{0}r^2 }.`

Now substitute E/2 for
`\frac{q}{4\pi\epsilon{0}r^2 }` in the above equation will get,

E'=E/2.

Therefore the electric field at distance r on +q charge is E/2.

Now the force xcan be calculated at the distance r on charge +2q will be

`F'=\frac{(q)(2q)}{4\pi\epsilon{0}r^2 }`

Substitute F for
`\frac{(q)(2q)}{4\pi\epsilon{0}r^2 }` in the above equation will give,

F'=F.

Therefore, the force exert on the +2q charge at the distance r will be F.