Question

Review Interactive Solution 4.47 in preparation for this problem. A 88.8-kg baseball player slides into second base. The coefficient of kinetic friction between the player and the ground is μk = 0.531. (a) What is the magnitude of the frictional force? (b) If the player comes to rest after 1.38 s, what is his initial speed?

Answer 1

frictional force = 462.56 N

initial velocity is 7.176 m/s

Step-by-step explanation:

given data

mass = 88.8 kg

μk = 0.531

to find out

magnitude and initial speed

solution

we know that frictional force equation that is

frictional force = μk Fn

put these value we get

frictional force = 0.531 (88.8) × (9.81)

frictional force = 462.56 N

and

initial speed calculate by force equation that is

force = mass × a

a = force / mass

a = 462.56 / 88.8

a = 5.20 m/s²

so we know

V =
`V_(0)` + at

`V_(0)` = 5.20 × 1.38

`V_(0)` = 7.176 m/s

so initial velocity is 7.176 m/s