Question

Find the value of x using the pythagorean theorem.

Do the side lengths form a pythagorean triple?

Answer 1

`{x}^(2) = {9}^(2) + {40}^(2) \\ {x}^(2) = 81 + 1600 \\ {x}^(2) = 1681 \\ x = √(1681) \\ x = 41`

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