Question

A manufacturer of rechargeable laptop batteries markets its batteries as having, on

average, 500 charges. A consumer group decides to test this claim by assessing the
number of times 30 of their laptop batteries can be recharged and finds the average is 497, with a standard deviation of 10.The resulting p-value is .1111; thus, the null hypothesis is not rejected. The consumer group concludes that the manufacturer.

Answer 1

Answer with explanation:-

Let
`\mu` be the population mean.

By considering the given information , we have

`H_0:\mu=500\\\\H_a:\mu\\eq500`, since the alternative hypothesis is two tailed , so the test is two tail test.

Given : Sample size : n=30

Sample mean :
`\overline{x}=497`

Then, Standard deviation :
`\sigma=10`

The p-value = 0.1111, the null hypothesis is not rejected.

Thus , we conclude that we have evidence to accept the company's claim that the batteries have on average 500 charges.