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The sum of the divisors function \sigma (n) is not a multiplicative function.
True
False

User Emrea
by
5.7k points

1 Answer

5 votes

Answer:

True.

Explanation:

If a function is multiplicative then it hold following properties

1.f(1)=1

2.
\f(a\cdot b)=f(a)\cdot f(b) hold for all a and b when even a and b are not co-prime.

Let
\sigma(n) is a function of sum of divisor of n


\sigma (n)=Sum of divisor of n

If n=1 then


\sigma (1)=1

It is satisfied first property.

Suppose n=9

Then divisor of 9=1,3,9

Sum of divisor=1+3+9=13

Divisor of 3=1,3

Sum of divisors of 3=1+3=4


\sigma (9)=13


\sigma (3)\cdot \sigma(3)=4\cdot 4=16

Hence,
\sigma (a\cdot b)\\eq \sigma(a)\cdot \sigma(b)

Therefore,
\sigma(n) is not a multiplicative function.

Hence, given statement is true.

User EBS
by
6.0k points