76.5k views
4 votes
The sum of the divisors function \sigma (n) is not a multiplicative function.
True
False

User Emrea
by
8.1k points

1 Answer

5 votes

Answer:

True.

Explanation:

If a function is multiplicative then it hold following properties

1.f(1)=1

2.
\f(a\cdot b)=f(a)\cdot f(b) hold for all a and b when even a and b are not co-prime.

Let
\sigma(n) is a function of sum of divisor of n


\sigma (n)=Sum of divisor of n

If n=1 then


\sigma (1)=1

It is satisfied first property.

Suppose n=9

Then divisor of 9=1,3,9

Sum of divisor=1+3+9=13

Divisor of 3=1,3

Sum of divisors of 3=1+3=4


\sigma (9)=13


\sigma (3)\cdot \sigma(3)=4\cdot 4=16

Hence,
\sigma (a\cdot b)\\eq \sigma(a)\cdot \sigma(b)

Therefore,
\sigma(n) is not a multiplicative function.

Hence, given statement is true.

User EBS
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.