Question

A rear wheel drive car of mass 1000 kg is accelerating with a constant acceleration without slipping from 0 to 60 m/s in 1 min. What will be friction force acting on each rear wheel of the car? 1000 N 60000 N 30000 N 500 N

Answer 1

Answer:The force that acts on the wheels equals 1000 Newtons

Step-by-step explanation:

We know acceleration is defined as

`a=(\Delta v)/(\Delta t)=(v_(2)-v_(1))/(t_(2)-t_(1))\\\\\therefore a=(60-0)/(60-0)=1m/s^(2)`

Now using newton's second law we have

`F_(ext)=m* a\\\\\therefore F_(ext)=1000* 1=1000N`