A rear wheel drive car of mass 1000 kg is accelerating with a constant acceleration without slipping from 0 to 60 m/s in 1 min. What will be friction force acting on each rear w…

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asked Jan 22, 2020 27.4k views

1 Answer

Mockman · Answer 1 · 2020-01-28T17:36:15+0000

Answer:The force that acts on the wheels equals 1000 Newtons

Step-by-step explanation:

We know acceleration is defined as

$a=(\Delta v)/(\Delta t)=(v_(2)-v_(1))/(t_(2)-t_(1))\\\\\therefore a=(60-0)/(60-0)=1m/s^(2)$

Now using newton's second law we have

$F_(ext)=m* a\\\\\therefore F_(ext)=1000* 1=1000N$