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Find the parametric equations for the line that passes through the points P (1,1,0) and Q (0,2,2).

1 Answer

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Answer:

The parametric equations for the given line are x=1-t, y=1+t and z=2t.

Explanation:

Given information: P (1,1,0) and Q (0,2,2).

The parametric equation of line are


x=x_0+at


y=y_0+bt


z=z_0+ct

where,
(x_0,y_0,z_0) is point on line and <a,b,c> is direction vector.

The line passes through the points P (1,1,0) and Q (0,2,2). So, the direction vector is


\overrightarrow{v}=<x_2-x_1, y_2-y_1, z_2-z_1>


\overrightarrow{v}=<0-1,2-1, 2-0>


\overrightarrow{v}=<-1,1,2>

The direction vector is <-1,1,2>. So, a=-1, b=1 and c=2. The parametric equation of line are


x=1+(-1)t=1-t


y=1+(1)t=1+t


z=0+(2)t=2t

Therefore the parametric equations for the given line are x=1-t, y=1+t and z=2t.

User Dale Emery
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