Question

A pharmaceutical company is attempting to make a large volume of nitrous oxide (NO). They predict they will be able to make a maximum amount of 7200 grams with the materials they have in stock. When the reaction is over they are able to collect 3784 grams of nitrous oxide. What was the percent yield of their process?

Answer 1

52.55% was the percent yield of their process.

Step-by-step explanation:

Amount of NO expected by pharmaceutical company = 7200 grams

Amount of NO actually obtained by pharmaceutical company = 3784 grams

To calculate the percentage yield, we use the equation:

`\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}* 100`

Experimental yield of nitrous oxide = 3784 grams

Theoretical yield of nitrous oxide = 7200 grams

`(3784 g)/(7200 g)* 100=52.55\%`

52.55% was the percent yield of their process.

Answer 2

The percent yield for NO reaction is 52.5%

Step-by-step explanation:

7200 grams is 100% or theoretical performance. X is real percent for NO reaction. In follow equation: 7200 x =3784, clearing x we have x = 3784/7200, so, x=0.52555, in percentage and it is multiply for 100 x=52.5%