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14. Solve: (a) 2y - 1/2 = -1/3 (b) 6 + 5 (a - 1) = 30

15. The sum of three consecutive integers is 48. Find the number. Plz answer quickly

1 Answer

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A)2y - 1/2 = -1/3

2y=-1/3+1/2

FIND THE LCM TO MAKE THE FRACTIONS LIKE FRACTIONS

LCM OF 3 AND 2 IS 6

-1/3*2=-2/6

1/2*3=3/6

-2/6+3/6=1/6

2y=1/6

y=1/6 ÷ 2

TAKING THE RECIPROCAL,

RECIPROCAL OF 2 IS 1/2

y=1/6*1/2

y=1/12

B) 6 + 5 (a - 1) = 30

6+(5)*(a)+(5)*(−1)=30(Distribute)

6+5a+−5=30

(5a)+(6+−5)=30(Combine Like Terms)

5a+1=30

5a=30-1

5a=29

a=29/5

15.sum of three consecutive integers=48

let the numbers be x ,x+1,x+2

x+x+1+x+2==48

3x+3=48

3x=48-3

3x=45

x=45/3

x=15

x+1=15+1=16

x+2=15+2=17

the numbers are 15,16,17

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