Question

Two chocolate frogs and one lollipop cost 78 cents. three chocolate frogs and 2 lollipops cost $1.32. find the cost for one chocolate frog and one lollipop

Hint x equal 30 cents and y equal 24 cents

Answer 1

x = $0.24 or 24 cent (chocolate frog cost $0.24 or 24 cent)

y = $0.3 or 30 cents (Lollipop cost $0.3 or 30 cents)

Explanation:

Let called chocolate frog is x and lollipop is y, we got:

2x + y = $0.78 (or 78 cent)

3x + 2y = $1.32

Now, we have to multiply the first equation by 2 then use it subtract for the second equation, we got:

4x + 2y = $1.56

-

3x + 2y = $1.32

4x - 3x + 2y - 2y = 1.56 - 1.32

x = $0.24 or 24 cent

Because x = 24 cent, or $0.24 sub it into 2x +y = $0.78, we got:

0.24*2 + y = $0.78

0.48 + y = $0.78

Subtract 0.48 from both sides, we got:

y = $0.3 or 30 cents

Hope this helped :3

Ps: My 'x' is your 'y' and my 'y' is your 'x' Sorry about that :(

Answer 2

Let the frogs be Y and the lollipops by X.

You have 2 frogs ( 2Y ) + 1 loliipop (X) = 0.78

And you have 3 frogs (3Y) + 2 lollipops (2X) = 1.32

The two equations are:

2Y + X = 0.78

3Y + 2X = 1.32

Multiply the first equation by -2:

-4Y - 2X = -1.56

Add that to the second equation:

-Y = -0.24

Multiply both sides by -1:

Y = 0.24

Now in the first equation replace Y with 0.24 and solve for X:

2(0.24) + X = 0.78

0.48 + x = 0.78

Subtract 0.48 from both sides:

X = 0.30

One Frog cost 0.24

One lollipop cost 0.30