Question

What is the average kinetic energy of hydrogen atoms on the 5500°C surface of the sun?

Answer 1

Answer: The average kinetic energy of hydrogen atoms is
`1.19562* 10^(-19)J`

Step-by-step explanation:

To calculate the average kinetic energy of the atom, we use the equation:

`K=(3)/(2)kT`

where,

K = average kinetic energy

k = Boltzmann constant =
`1.3807* 10^(-23)J/K`

T = temperature =
`5500^oC=[5500+273]K=5773K`

Putting values in above equation, we get:

`K=(3)/(2)* 1.3807* 10^(-23)J/K* 5773K\\\\K=1.19562* 10^(-19)J`

Hence, the average kinetic energy of hydrogen atoms is
`1.19562* 10^(-19)J`