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If 2/√3+√5 + 5/√3-√5 = a√3 +b√5 find a and b

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Answer:

2/√3+√5 + 5/√3-√5 = a√3 +b√5

Add fractions.

7/√3+2√5

To have √3 in numerator multiply both sides of raction by √3.

(7√3)/3+2√5 = a√3 +b√5, thus a = 7/3 and b = 2:

Make sure you wrote the equation write, because Im not sure about that.

User Michael Kunst
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