Answer:
Part a)
![s=(d)/(√(3))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/67axhiidlinoc36enyieafdezcoe22fn4j.png)
Part b)
or
Explanation:
Part a) Solve the formula for S
we have
![d=s√(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/jy7e50ozc2jfkb5crkp4nfeb4l4x6wx4sz.png)
Solve for s
That means-----> isolate the variable s
Divide by √3 both sides
![(d)/(√(3))=(s√(3))/(√(3))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/v9ctlateds2pbn8yfzhjnw8hyquesf9gzz.png)
![s=(d)/(√(3))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/67axhiidlinoc36enyieafdezcoe22fn4j.png)
Part b) Find the value of S when d = 15 inches
we have
![s=(d)/(√(3))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/67axhiidlinoc36enyieafdezcoe22fn4j.png)
substitute the value of d=15 in in the formula and solve for s
![s=(15)/(√(3))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/caq6z4dxyxne8u40jimmedazp104aecom8.png)
Simplify
![s=(15)/(√(3))(√(3))/(√(3))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/32jjub5cpq9ncqzbvnf6zq62rhlydb41fo.png)
-----> exact value
-----> approximate value