Question

Find the area of triangle jkl above if the vertices are j(2,2), k(3,5), and L(6,2)

Answer 1

`Area=6\:units^2`

Explanation:

Given the vertices
`(x_1,y_1)=J(2,2)`,
`(x_2,y_2)=K(3,5)` and

`(x_3,y_3)=L(6,2)`. The area of triangle JKL is given by:

`Area=(1)/(2)|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)|`

We substitute the values to get:

`Area=(1)/(2)|2(5-2)+3(2-2)+6(2-5)|`

This simplifies to

`Area=(1)/(2)|2(3)+3(0)+6(-3)|`

`Area=(1)/(2)|6+0-18|`

`Area=(1)/(2)|-12|`

`Area=(1)/(2)*12`

`Area=6\:units^2`