Find the area of triangle jkl above if the vertices are j(2,2), k(3,5), and L(6,2)

Question

asked Sep 20, 2020 72.8k views

1 Answer

Malcolm Box · Answer 1 · 2020-09-25T01:30:56+0000

Answer:

$Area=6\:units^2$

Explanation:

Given the vertices
(x_1,y_1)=J(2,2) ,
(x_2,y_2)=K(3,5) and

(x_3,y_3)=L(6,2) . The area of triangle JKL is given by:

Area=(1)/(2)|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)|

We substitute the values to get:

Area=(1)/(2)|2(5-2)+3(2-2)+6(2-5)|

This simplifies to

Area=(1)/(2)|2(3)+3(0)+6(-3)|

Area=(1)/(2)|6+0-18|

Area=(1)/(2)|-12|

Area=(1)/(2)*12

$Area=6\:units^2$