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What is the radius of a circle whose equation is x2+y2−10x+6y+18=0?

User Tom Carr
by
5.5k points

2 Answers

5 votes

Answer:

B) 4 units.

Explanation:

User Andrew Bobulsky
by
5.8k points
4 votes

Answer:

The radius is 4 units....

Explanation:

We can find the radius of a circle through the following procedure:

Complete the square for x and y

Put in the format for a circle. (x-h)² + (y-k)² = r², center at (h,k) with radius = r

x2+y2−10x+6y+18=0

Now subtract 18 from both sides.

x^2+y^2−10x+6y+18-18=0-18

x^2 - 10x + y^2 + 6y = -18

(x-5)^2 - 25 + (y+3)^2 - 9 = -18

(x-5)^2 + (y+3)^2 = -18+9+25

(x-5)^2 + (y+3)^2 = 16

So,

r^2 = 16

Take square root at both sides:

√r^2 = √16

r = 4

Thus the radius is 4 units....

User Ksbg
by
5.2k points