Question

Sample A is a brand of supplement that contains iron in the form of 324mg ferrous gluconate C12H24FeO14 per tablet. What is the amount of elemental iron in one table of Sample A?

Answer 1

Amount of elemental iron in sample A is 0.0405g.

Step-by-step explanation:

Molar mass of C = 12 g/mol

Molar mass of H = 1 g/mol

Molar mass of Fe = 56 g/mol

Molar mass of O = 16 g/mol

So, molar mass of ferrous gluconate =
`(12* 12)g+(24* 1)g+(1* 56)g+(14* 16)g=448g`

So number of mole of ferrous gluconate in 324 mg =
`(0.324)/(448)moles`

(number of moles =
`(mass)/(molar mass)`)

As 1 mol of ferrous gluconate contains 1 mol of Fe therefore
`(0.324)/(448)moles` of ferrous gluconate contain
`(0.324)/(448)moles` of Fe.

So amount of elemental iron in sample A =
`(0.324)/(448)* 56g=0.0405g`