Question

If water (p=998 kg/m3, u = 10-3 Pa.s) flows through a 50 m Pa.s) determine the velocity of carbon tetrac me the velocity of carbon tetrachloride (p = 1590 kg/m", u = 0.958 x 10 howing through a 60 mm-diameter pipe so that they both have the same dynamic characteristics (Reynolds number similarity, Re = puD/).

Answer 1

Step-by-step explanation:

As it is given that both have same dynamic characteristics.

Therefore,
`Re_(water)` =
`Re_{CCl_(4)}`

`(\rho_(water) * \\u_(water) * D_(water))/(\mu_(water))` =
`\frac{\rho_{CCl_(4)} * \\u_{CCl_(4)} * D_{CCl_(4)}}{\mu_{CCl_(4)}}`

Hence, putting the given values into the above formula as follows.

`(998 kg/m^(3) * 2 m/s * 50 mm)/(10^(-3)Pa.s)` =
`\frac{1590 kg/m^(3)} * \\u_{CCl_(4)} * 60 mm}{0.958 * 10^(-3)}`

`\\u_{CCl_(4)}` = 1.002 m/s

Thus, we can conclude that the velocity of carbon tetrachloride in the given conditions is 1.002 m/s.