Answer:
The correct answer is option 'c': 30 AUs
Step-by-step explanation:
For a spherical wave front emitted by sun with total energy 'E' the energy density over the surface when it is at a distance 'r' from the sun is given by
![e=(E)/(4\pi r^(2))](https://img.qammunity.org/2020/formulas/physics/college/bl7ytwjrtnwfhfm4zvqi29fbq65ymbtjpv.png)
This energy per unit area is sensed by observer as intensity of the sun.
Let the initial intensity of sun at a distance
be
![e_(1)](https://img.qammunity.org/2020/formulas/physics/college/w6xah3st417md8x3j6ihup3obur8zp9umn.png)
Thus if the sun becomes 900 times dimmer we have
![e'=(e_(1))/(900)\\\\(E)/(4\pi r_(2)^(2))=(1)/(900)* (E)/(4\pi r_(1)^(2))\\\\\Rightarrow r_(2)^(2)={r_(1)^(2)}* 900\\\\\therefore r_(2)={r_(1)}* {30}](https://img.qammunity.org/2020/formulas/physics/college/q2xzeb3um3iik8kpcfv138pj8r44srtqa2.png)
Thus the distance increases 30 times.