154k views
0 votes
zaachary had ten more super hero stickers than Andrew, so he gave Andrew half of his stickers. Then Andrew had more stickers than Zachary, so he gave Zachary four stickers. Then they both had thirteen stickers. How many stickers did each boy have originally?

2 Answers

4 votes
Zachary had 18 and Andrew had 8
User WYi
by
5.2k points
4 votes

Answer:

Number of stickers with Andrew= 8

and

Number of stickers with Zachary= 18

Explanation:

Let Andrew originally had: x stickers.

and Zachary had: (x+10) stickers.

( Since, Zachary had ten more super hero stickers than Andrew )

Now, Zachary gave Andrew half of his stickers )

i.e.


\text{Now number of stickers left with Zachary}=(1)/(2)(x+10)

and


\text{Number of stickers  with Andrew}=x+(1)/(2)(x+10)

Then Andrew had more stickers than Zachary, so he gave Zachary four stickers.

Now,


\text{The number of stickers with Andrew}=x+(1)/(2)(x+10)-4

and


\text{Number of stickers with Zachary}=(1)/(2)(x+10)+4

Now, they both had 13 stickers.

i.e.


(1)/(2)(x+10)+4=13

i.e.


(1)/(2)(x+10)=13-4\\\\(1)/(2)(x+10)=9\\\\x+10=2* 9\\\\x+10=18\\\\x=18-10\\\\x=8

Hence,

Number of stickers with Zachary= 18 stickers

( since, x+10=8+10=18 )

and

Number of stickers with Andrew= 8 stickers

User Epstone
by
5.4k points