Question

If a solenoid has the length of 10 cm and has 2000 turns what is the electric current required to create a magnetic field inside of a solenoid of 0.4T.

Answer 1

15.92 A

Step-by-step explanation:

L = length of the solenoid = 10 cm = 0.10 m

N = Number of turns of the solenoid = 2000

B = magnitude of magnetic field inside the solenoid = 0.4 T

i = magnitude of electric current in the solenoid

Magnetic field inside the solenoid is given as

`B = (\mu _(o)Ni)/(L)`

`0.4 = ((12.56* 10^(-7))(2000)i)/(0.10)`

i = 15.92 A