Answer:
C) 20.23 μF
Step-by-step explanation:
R = resistance of the resistor = 15 ohm
L = inductance of the inductor = 11.5 mH = 0.0115 H
f = resonance frequency achieved = frequency of applied voltage = 330 Hz
C = Capacitance of the capacitor
For resonance to be possible


C = 20.23 x 10⁻⁶ F
C = 20.23 μF