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√40x²y6 how do you simplify this radical​

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\bf √(40x^2y^6)\qquad \begin{cases} 40=&2\cdot 2\cdot 2\cdot 5\\ &2^2\cdot 10\\ y^6=&y^(3\cdot 2)\\ &(y^3)^2 \end{cases}\implies √(2^2\cdot 10x^2(y^3)^2)\implies 2xy^3√(10)

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