Question

An object of 6 cm height is 16 cm in front of a converging lens with focal length of magnitude 4 cm. What is the dimension of the image(include the unit and if it is the case the sign)?

Answer 1

`- 2` cm

Step-by-step explanation:

`h_(o)` = height of the object = 6 cm

`d_(o)` = distance of the object from the lens = 16 cm

`f` = focal length of the lens = 4 cm

`d_(i)` = image distance

using the lens equation

`(1)/(d_(o)) + (1)/(d_(i)) = (1)/(f)`

`(1)/(16) + (1)/(d_(i)) = (1)/(4)`

`d_(i) = (16)/(3)` cm

`h_(i)` = height of the image

Using the equation

`(h_(i))/(h_(o)) = (- d_(i))/(d_(o))`

`(h_(i))/(6) = (- (16)/(3))/(16)`

`h_(i) =-2` cm